Retry Tool Calls with Exponential Backoff

Wrap a flaky tool with retries, exponential backoff, and a max wall-clock budget.

Problem statement

Pro

Full problem description visible. Upgrade to unlock the editor, test cases, and solution.

Implement call_with_retry(fn, *args, max_attempts=5, base=0.5, max_seconds=10). - Retry on any exception. - Sleep base * 2**attempt seconds between attempts (with small jitter). - Stop if cumulative wait exceeds max_seconds or attempts exhausted. - Re-raise the last exception on failure.

Limited Period Offer

Unlock with Pro

₹149/month85% OFF

₹999/monthLimited period launch pricing.

Get the full problem statement, test cases, interactive editor, solution explanation, and visual diagram.

Upgrade to Pro Have a student code?

solution.py

import time, random

def call_with_retry(fn, *args, max_attempts=5, base=0.5, max_seconds=10, **kwargs):
    elapsed = 0.0
    last_exc = None
    for attempt in range(max_attempts):
        try:
            return fn(*args, **kwargs)
        except Exception as e:
            last_exc = e

Backoff + budget check

    raise last_exc

Editor locked

Upgrade to Pro to write and run code.

Upgrade to Pro

Already have Pro access? Sign in